Data and calculations<\/p>\n
Standarization of silver nitrate<\/p>\n
Standard NaCl titration trials<\/p>\n
Trial<\/p>\n
NaCl (weight)<\/p>\n
End Point<\/p>\n
1<\/p>\n
0.2377 g<\/p>\n
13.83 mL<\/p>\n
2<\/p>\n
0.2430 g<\/p>\n
14.00 mL<\/p>\n
3<\/p>\n
0.2563 g<\/p>\n
14.70 mL<\/p>\n
Titrant (AgNO3) added volume (Vt):<\/p>\n
Trial 1<\/p>\n
Vt = 13.83 mL<\/p>\n
Trial 2<\/p>\n
Vt = 14.00 mL<\/p>\n
Trial 3<\/p>\n
Vt = 14.70 mL<\/p>\n
Reaction<\/p>\n
NaCl + AgNO3 AgCl (s) + NaNO3<\/p>\n
1 mol NaCl = 1 mol AgNO3<\/p>\n
NaCl moles calculations (MW NaCl = 58.44 g\/mol)<\/p>\n
Trial 1<\/p>\n
Mol NaCl = (0.2377 g) x (1mol\/58.44g) = 4.0674 mmol NaCl = mmol AgNO3<\/p>\n
Trial 2<\/p>\n
Mol NaCl = (0.2430 g) x (1mol\/58.44g) = 4.1581 mmol NaCl = mmol AgNO3<\/p>\n
Trial 3<\/p>\n
Mol NaCl = (0.2563 g) x (1mol\/58.44g) = 4.3857 mmol NaCl = mmol AgNO3<\/p>\n
Real [AgNO3]<\/p>\n
[AgNO3] = Mol \/ Vt<\/p>\n
Trial 1<\/p>\n
[AgNO3] = (4.0674 mmol AgNO3)\/(13.83 mL) = 0.2940 M<\/p>\n
Trial 2<\/p>\n
[AgNO3] = (4.1581 mmol AgNO3)\/(14.00 mL) = 0.2970 M<\/p>\n
Trial 3<\/p>\n
[AgNO3] = (4.3857 mmol AgNO3)\/(14.70 mL) = 0.2983 M<\/p>\n
Mean [AgNO3]<\/p>\n
Mean [AgNO3] = ([AgNO3]1 + [AgNO3]2 + [AgNO3]3 + [AgNO3]4) \/ 3<\/p>\n
[AgNO3] = (0.2940 M + 0.2970 M + 0.29283 M) \/ 3 = 0.2964 M<\/p>\n
Determination of an unknown<\/p>\n
Sample<\/p>\n
Unknown weight<\/p>\n
End Point<\/p>\n
1<\/p>\n
0.4279 g<\/p>\n
22.93 mL<\/p>\n
2<\/p>\n
0.3447 g<\/p>\n
18.30 mL<\/p>\n
3<\/p>\n
0.4002 g<\/p>\n
21.10 mL<\/p>\n
Titrant (AgNO3) added volume (Vt):<\/p>\n
Trial 1<\/p>\n
Vt = 22.93 mL<\/p>\n
Trial 2<\/p>\n
Vt = 18.30 mL<\/p>\n
Trial 3<\/p>\n
Vt = 21.10 mL<\/p>\n
Reaction<\/p>\n
Cl- + AgNO3 AgCl (s) + NO3-<\/p>\n
1 mol NaCl = 1 mol AgNO3<\/p>\n
Moles AgNO3 added ([AgNO3] = 0.4718 M)<\/p>\n
Moles AgNO3 = [AgNO3] x Vt<\/p>\n
Sample 1<\/p>\n
Moles AgNO3 = (0.2964 M) x (22.93 mL) x (1 L\/1000 mL) = 6.7964 mmol AgNO3 = mmol Cl-<\/p>\n
Sample 2<\/p>\n
Moles AgNO3 = (0.2964 M) x (18.30 mL) x (1 L\/1000 mL) = 5.4241 mmol AgNO3 = mmol Cl-<\/p>\n
Sample 3<\/p>\n
Moles AgNO3 = (0.2964 M) x (21.10 mL) x (1 L\/1000 mL) = 6.2540 mmol AgNO3 = mmol Cl-<\/p>\n
Mass Cl- (AM Cl = 35.5 g\/mol)<\/p>\n
Sample 1<\/p>\n
Mass Cl- = (6.7964 mmol Cl-) x (1 mol\/1000 mmol) x (35.5 g\/mol) = 0.2412 g Cl-<\/p>\n
Sample 2<\/p>\n
Mass Cl- = (5.4241 mmol Cl-) x (1 mol\/1000 mmol) x (35.5 g\/mol) = 0.1925 g Cl-<\/p>\n
Sample 3<\/p>\n
Mass Cl- = (5.9576 mmol Cl-) x (1 mol\/1000 mmol) x (35.5 g\/mol) = 0.2220 g Cl-<\/p>\n
% Cl- <\/p>\n
% Cl- = [(g Cl-) \/ (g sample)] x 100%<\/p>\n
Sample 1<\/p>\n
% Cl- = [(0.2412g) \/ (0.4279 g)] x 100% = 56.37%<\/p>\n
Sample 2<\/p>\n
% Cl- = [(0.1925g) \/ (0.3447 g)] x 100% = 55.84%<\/p>\n
Sample 3<\/p>\n
% Cl- = [(0.2115g) \/ (0.4002 g)] x 100% = 55.48%<\/p>\n
Mean % Cl- <\/p>\n
Mean % Cl- = [(g Cl-)1 + (g Cl-)2 + (g Cl-)3 ] \/ 3<\/p>\n
Mean % Cl- = [ 56.37% + 55.84% + 55.48%] \/ 3 = 55.90%<\/p>\n
Part 3<\/p>\n
Sample<\/p>\n
Mass<\/p>\n
Crucible filter<\/p>\n
Crusible filter w\/AgNO3<\/p>\n
AgNO3<\/p>\n
1<\/p>\n
0.4148 g<\/p>\n
30.2707 g<\/p>\n
31.2109 g<\/p>\n
0.9402 g<\/p>\n
2<\/p>\n
0.4095 g<\/p>\n
31.0544 g<\/p>\n
31.9894 g<\/p>\n
0.9350 g<\/p>\n
3<\/p>\n
0.4053 g<\/p>\n
30.7135 g<\/p>\n
31.6364 g<\/p>\n
0.9220 g<\/p>\n
4<\/p>\n
04103 g<\/p>\n
30.7341 g<\/p>\n
31.6651 g<\/p>\n
0.9310 g<\/p>\n
Mass Cl- (AM Cl = 35.5 g\/mol, MM AgNO3 = 143.32 g\/mol))<\/p>\n
Mass Cl- = (Mass AgNO3) x (1 mol AgNO3\/143.32 g AgNO3) x (1 mol Cl-\/1 mol AgNO3) x (35.45 g\/molCl)<\/p>\n
Sample 1<\/p>\n
Mass Cl- = (0.9402 g) x (1 mol AgNO3\/143.32 g AgNO3) x (1 mol Cl-\/1 mol AgNO3) x (35.45 g\/molCl) = 0.2326 g Cl- <\/p>\n
Sample 2<\/p>\n
Mass Cl- = (0.9350 g) x (1 mol AgNO3\/143.32 g AgNO3) x (1 mol Cl-\/1 mol AgNO3) x (35.45 g\/molCl) = 0.2313 g Cl-<\/p>\n
Sample 3<\/p>\n
Mass Cl- = (0.9220 g) x (1 mol AgNO3\/143.32 g AgNO3) x (1 mol Cl-\/1 mol AgNO3) x (35.45 g\/molCl) = 0.2283 g Cl-<\/p>\n
Sample 4<\/p>\n
Mass Cl- = (0.9310 g) x (1 mol AgNO3\/143.32 g AgNO3) x (1 mol Cl-\/1 mol AgNO3) x (35.45 g\/molCl) = 0.2303 g Cl-<\/p>\n
% Cl- <\/p>\n
% Cl- = [(g Cl-) \/ (g sample)] x 100%<\/p>\n
Sample 1<\/p>\n
% Cl- = [(0.2326g) \/ (0.4148 g)] x 100% = 56.08%<\/p>\n
Sample 2<\/p>\n
% Cl- = [(0.2313g) \/ (0.4095 g)] x 100% = 56.48%<\/p>\n
Sample 3<\/p>\n
% Cl- = [(0.2283g) \/ (0.3447 g)] x 100% = 56.58%<\/p>\n
Sample 4<\/p>\n
% Cl- = [(0.2303g) \/ (0.4103 g)] x 100% = 56.13%<\/p>\n
Mean % Cl- <\/p>\n
Mean % Cl- = [(g Cl-)1 + (g Cl-)2 + (g Cl-)3 + (g Cl-)4] \/ 4<\/p>\n
Mean % Cl- = [56.08% + 56.48% + 56.58% + 56.13%] \/ 4 = 56.32%<\/p>\n
Reference:<\/p>\n
Harris, D.C., Lucy, C.A., Quantitative Chemical Analysis, 10th Ed; W.H. Freeman and Company: NY, 2020<\/p>\n","protected":false},"excerpt":{"rendered":"
Data and calculations Standarization of silver nitrate Standard NaCl titration trials Trial NaCl (weight) End Point 1 0.2377 g 13.83 mL 2 0.2430 g 14.00 mL 3 0.2563 g 14.70 mL Titrant (AgNO3) added volume (Vt): Trial 1 Vt = 13.83 mL Trial 2 Vt = 14.00 mL Trial 3 Vt = 14.70 mL Reaction […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[10],"class_list":["post-79329","post","type-post","status-publish","format-standard","hentry","category-research-paper-writing","tag-writing"],"_links":{"self":[{"href":"https:\/\/papersspot.com\/blog\/wp-json\/wp\/v2\/posts\/79329","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/papersspot.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/papersspot.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/papersspot.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/papersspot.com\/blog\/wp-json\/wp\/v2\/comments?post=79329"}],"version-history":[{"count":0,"href":"https:\/\/papersspot.com\/blog\/wp-json\/wp\/v2\/posts\/79329\/revisions"}],"wp:attachment":[{"href":"https:\/\/papersspot.com\/blog\/wp-json\/wp\/v2\/media?parent=79329"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/papersspot.com\/blog\/wp-json\/wp\/v2\/categories?post=79329"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/papersspot.com\/blog\/wp-json\/wp\/v2\/tags?post=79329"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}