Given that a box contains 12 spiders of which 3 are tarantulas 4 black widows and 5 jumping spide

Given that a box contains 12 spiders, of
which 3 are tarantulas, 4 black widows, and 5 jumping spiders. If we choose 2 with replacement, what is the probability of getting one black widow and one that is not a black widow. If we choose them without replacement, the probabilities would change from the first selection to the second. But choosing with replacement means the probabilities don’t change from the first to
the second selection. Then clearly the two events (first choice and second choice) are independent events.
Now the probability of choosing a black widow is P(B) = 4/12 = 1/3 since there are 4 black
widows in the 12 spiders.
And the probability of choosing one that is not a black widow is P(B) = 8/12 = 2/3.
Since these events are independent, we could use the formula for independent events, which is
P(B and B) = P(B) · P(B) = 1/3 · 2/3 = 2/9 = 22.2%.
The reasoning seems correct, the only problem with this is that it gives the wrong answer! For this
assignment, explain in detail why the formula, in this case, gives an answer that is not correct.

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